ft_itoa.c

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/* ************************************************************************** */
/*                                                                            */
/*                                                        :::      ::::::::   */
/*   ft_itoa.c                                          :+:      :+:    :+:   */
/*                                                    +:+ +:+         +:+     */
/*   By: rmikhayl <rmikhayl@student.42london.c      +#+  +:+       +#+        */
/*                                                +#+#+#+#+#+   +#+           */
/*   Created: 2023/12/17 17:25:28 by rmikhayl          #+#    #+#             */
/*   Updated: 2023/12/17 17:25:28 by rmikhayl         ###   ########.fr       */
/*                                                                            */
/* ************************************************************************** */
 
#include "libft.h"
 
/* *************************** ft_itoa ************************************** */
/*   Allocates and returns a string representing the integer 'n'.             */
/*   Handles negative numbers. Returns NULL on allocation failure.            */
/*                                                                            */
/*   In layman's terms: It converts an integer into a string of characters,   */
/*   taking care of whether the number is positive or negative.               */
/* ************************************************************************** */
 
static int  count_digits(int n)
{
    int count;
 
    count = 0;
    if (n <= 0)
        count = 1;
    else
        count = 0;
    while (n != 0)
    {
        count++;
        n /= 10;
    }
    return (count);
}
 
char    *ft_itoa(int n)
{
    int     len;
    char    *str;
 
    if (n == INT_MIN)
        return (ft_strdup("-2147483648"));
    if (n == 0)
        return (ft_strdup("0"));
    len = count_digits(n);
    str = (char *)malloc(len + 1);
    if (!str)
        return (NULL);
    str[len--] = '\0';
    if (n < 0)
    {
        str[0] = '-';
        n = -n;
    }
    while (n)
    {
        str[len--] = n % 10 + '0';
        n /= 10;
    }
    return (str);
}